The random variable X has mean 1 and variance 1. Find P(X >= 2) if X has an exponential distribution. Give your answer precise to three decimal places, e.g., 0.723, 0.488, 0.267.
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The mean of an exponential distribution is 1/λ and the variance is 1/λ^2. Given that the mean and variance of X are both 1, we can deduce that λ = 1. The cumulative distribution function (CDF) of an exponential distribution is F(x) = 1 - e^(-λx). This gives the Show more…
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