Question

Let $x(t) = e^t \cos(6t)$, $y(t) = e^t \sin(5t)$. Find $\frac{dy}{dx}$. Assume $\frac{dx}{dt} \neq 0$. (Express numbers in exact form. Use symbolic notation and fractions where needed.) $\frac{dy}{dx} = \frac{\cos(6t) - 6\sin(6t)}{\sin(5t) + 5\sin(5t)}$ Incorrect

          Let $x(t) = e^t \cos(6t)$, $y(t) = e^t \sin(5t)$. Find $\frac{dy}{dx}$. Assume $\frac{dx}{dt} \neq 0$.
(Express numbers in exact form. Use symbolic notation and fractions where needed.)
$\frac{dy}{dx} = \frac{\cos(6t) - 6\sin(6t)}{\sin(5t) + 5\sin(5t)}$
Incorrect

$Let x(t) = e^t cos(6t), y(t) = e^t sin(5t). Find (dy)/(dx). Assume (dx)/(dt)≠ 0. (Express numbers in exact form. Use symbolic notation and fractions where needed.) (dy)/(dx) = (cos(6t) - 6sin(6t))/(sin(5t) + 5sin(5t)) Incorrect$

Added by Christopher N.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/22/2023

Step 1

Using the chain rule, we have: dx/dt = e^t*(-sin(6t) + 6cos(6t)) dy/dt = e^t*(cos(5t) + 5sin(5t)) Show more…

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Let x(t)=e^(t)cos(6t),y(t)=e^(t)sin(5t). Find (dy)/(dx). Assume (dx)/(dt)!=0. (Express numbers in exact form. Use symbolic notation and fractions where needed.) (dy)/(dx)=|((cos(6t)-6sin(6t)))/((sin(5t)+5sin(5t))) Let x(t) = e' cos (6t), y(t) = e' sin (5t). Find Assume e dx#0. dx dt Express numbers in exact form.Use symbolic notation and fractions where needed. dy dx (cos(6t)-6sin(6t)) sin(5t)+5 sin(5t)) Incorrect