00:01
Hello, let's have a look at the question.
00:02
So the question state, let yt represent your bank account balance in dollars after t years.
00:09
Suppose you start with $80 ,000 in the account.
00:14
So we are starting with $80 ,000 in the bank account and each year the account earns 6 % interest and you deposit $3 ,000 into the account and this can be modeled with the differential equation as dy by dt is equal to 0 .06y plus 3 ,000 and y at 0 is equal to 80 ,000.
00:52
So we have to solve this differential equation for yt.
00:56
Now here we can write that dy by dt minus 0 .06y is equal to 3 ,000.
01:07
So let us find here the integrating factor which can be calculated by e to the power integration of minus 0 .06 dx.
01:20
So on solving here we will get this as e to the power minus 0 .06t.
01:28
Now let us multiply this integrating factor in our differential equation.
01:34
So we will get y multiplied with e to the power minus 0 .06t is equal to integration of 3 ,000 and multiplied with e to the power minus 0 .06t and dt...