Light of wavelength 610 nm is incident on a slit of width 0.20 mm, and a diffraction pattern is produced on a screen that is 2.0 m from the slit. What is the distance of the second dark fringe from the center of the central bright fringe?
Added by Stacy C.
Step 1
20 mm. Plugging in the values, we get: θ = sin^(-1)(2 * 610 nm / 0.20 mm) θ = sin^(-1)(1220 nm / 0.20 mm) θ = sin^(-1)(6.1) θ ≈ 0.7° Show more…
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