\( \lim _{x \rightarrow 1} \frac{e^{\tan (\ln x)}-x^{3}}{\ln x+\sin (x-1)} \) is equal to A 1 (B) -1 (C) 0 D does not exist
Added by Keith S.
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Step 1
As \( x \to 1 \), both the numerator and the denominator approach 0, resulting in an indeterminate form \(\frac{0}{0}\). We can apply L'Hôpital's Rule. Show more…
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