Question

lim x->0 (x^2 sin(x))/(sin(x) - x)

          lim x->0 (x^2 sin(x))/(sin(x) - x)
        

Added by Richard H.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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lim x->0 (x^2 sin(x))/(sin(x) - x)
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Transcript

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00:01 Hi there, so for this problem we have the limit of x that approaches zero by the right of the nibirian logarithm of x divided by x.
00:17 Now we need to solve this limit.
00:21 Now if we evaluate this right away we know that we cannot use the lyapunov rule.
00:28 This is because we will have that if we evaluate this by zero by the right we obtain minus infinity divided by zero and now we know that we can only use lyapunov's rule if we have a determination of the type zero divided by zero or infinity divided by infinity...
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