Question

\lim_{x \to 3^{+}} \frac{2x - 6}{|3 - x|} = -2 Select one: True False

          \lim_{x \to 3^{+}} \frac{2x - 6}{|3 - x|} = -2
Select one:
True
False
        
limx →3^+ (2x - 6)/(|3 - x|) = -2
Select one:
True
False

Added by Michael G.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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lim_(x->3^(+))(2x-6)/(|3-x|)=-2 Select one: True False 2x-6 lim =-2 x-3+ |3-x| Select one: True False
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Transcript

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00:01 This problem gives us three limits, and it wants us to determine if the limit is true or false.
00:05 So we're going to determine this by looking at these polynomials that we're evaluating the limit for, and remember what their behaviors are for their in behaviors.
00:13 So first for our limit as x approaches negative infinity, that means our polynomial that we're traveling on.
00:19 We're traveling to the left on it.
00:21 And this polynomial has a degree that's odd with a negative leading coefficient.
00:25 When that happens, the end behavior is that the left side goes up.
00:29 We have behavior in the middle of the polynomial, and the right side goes down.
00:33 So to determine if this is true, this is saying, as we move to the left, we approach positive infinity.
00:39 That is correct with the end behavior we know to be true, because as we move to the left on our polynomial, our end behavior goes up, which does approach positive infinity.
00:47 So our first statement is true.
00:49 Our next statement, we have an even degree with a positive leading coefficient...
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