Question

Line k has the equation $y = (-\frac{1}{2})x - 3$. Line $l$ is parallel to line k, but passes through the point $(2, -5)$. Find an equation for line $l$ in both slope-intercept form and point-slope form using the given point. An equation for $l$ in slope-intercept form is: An equation for $l$ in point-slope form is:

          Line k has the equation $y = (-\frac{1}{2})x - 3$.
Line $l$ is parallel to line k, but passes through the point $(2, -5)$.
Find an equation for line $l$ in both slope-intercept form and point-slope form using the given point.
An equation for $l$ in slope-intercept form is:
An equation for $l$ in point-slope form is:

Line k has the equation y = (-(1)/(2))x - 3.
Line l is parallel to line k, but passes through the point (2, -5).
Find an equation for line l in both slope-intercept form and point-slope form using the given point.
An equation for l in slope-intercept form is:
An equation for l in point-slope form is:

Added by Matthew F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Babita Kumari

07/14/2021

Step 1

The equation of line k is y = -3, which means the slope is 0. Therefore, the slope of line l will also be 0. Show more…

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Line k has the equation y = -3. Line l is parallel to line k, but passes through the point (2, -5). Find an equation for line l in both slope-intercept form and point-slope form using the given point. An equation for line l in slope-intercept form is y = mx + b. An equation for line l in point-slope form is y - y1 = m(x - x1).