Question

Line tangent to an implicitly defined curve. Find the equation of the line tangent to the graph of $\left(\frac{36}{35}\right)x^3 + \left(\frac{36}{35}\right)y^3 - 6xy = 0$ at the point $(3, 2)$. Type answer in form $y = mx + b$.

          Line tangent to an implicitly defined curve.
Find the equation of the line tangent to the graph of $\left(\frac{36}{35}\right)x^3 + \left(\frac{36}{35}\right)y^3 - 6xy = 0$ at the point $(3, 2)$.
Type answer in form $y = mx + b$.

Line tangent to an implicitly defined curve.
Find the equation of the line tangent to the graph of ((36)/(35))x^3 + ((36)/(35))y^3 - 6xy = 0 at the point (3, 2).
Type answer in form y = mx + b.

Added by Zachary L.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zack A

11/25/2023

Step 1

To find the equation of the tangent line, we first need to find the derivative of the curve equation. The given curve equation is ((36)/(35))x^(3)+((36)/(35))y^(3)-6xy=0. Taking the derivative with respect to x, we get: d/dx [((36)/(35))x^(3)+((36)/(35))y^(3)-6xy] Show more…

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Line tangent to an implicitly defined curve. Find the equation of the line tangent to the graph of ((36)/(35))x^(3)+((36)/(35))y^(3)-6xy=0 at the point (3,2). Type answer in form y=mx+b. Line tangent to an implicitly defined curve Find the equation of the line tangent to the graph of (36)3+36y36y=0 at the point (3,2 Type answer in form y=m+b