Question

Linearization Consider the following function: g(x) = cos²x + cos x. Linearize the function about x = \frac{\pi}{2}. Store your result in a variable \texttt{lin}, which should be a \texttt{sympy} expression. You should remove the spurious O term by calling the method \texttt{removeO()} on the result of the linearization. Starter code (click to view) Answer* 1 import sympy 2 x = sympy.S('x') 3 g = (sympy.cos(x))**2 + sympy.cos(x) 4 5 lin = sympy.series(g,x,sympy.pi/2) 6 lin = lin.removeO() 1 point

          Linearization
Consider the following function:
g(x) = cos²x + cos x.
Linearize the function about x = \frac{\pi}{2}. Store your result in a variable \texttt{lin}, which should be a \texttt{sympy} expression.
You should remove the spurious O term by calling the method \texttt{removeO()} on the result of the linearization.
Starter code (click to view)
Answer*
1 import sympy
2 x = sympy.S('x')
3 g = (sympy.cos(x))**2 + sympy.cos(x)
4
5 lin = sympy.series(g,x,sympy.pi/2)
6 lin = lin.removeO()
1 point

Linearization
Consider the following function:
g(x) = cos²x + cos x.
Linearize the function about x = (π)/(2). Store your result in a variable lin, which should be a sympy expression.
You should remove the spurious O term by calling the method removeO() on the result of the linearization.
Starter code (click to view)
Answer*
1 import sympy
2 x = sympy.S('x')
3 g = (sympy.cos(x))**2 + sympy.cos(x)
4
5 lin = sympy.series(g,x,sympy.pi/2)
6 lin = lin.removeO()
1 point

Added by Ann D.

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