Question

Lithium reacts spontaneously with bromine to produce lithium bromide. If 25.0 g of lithium and 25.0 g of bromine are present at the beginning of the reaction, determine the grams of LiBr produced. 2 Li + Br2 ? 2 LiBr

Name: lithium reacts spontaneously with bromine to produce lithium bromide if 250 g of lithium and 250 g of bromine are present at the beginning of the reaction determine the grams of libr produced 2 li b 2
Uploaded: 2021-10-25T04:19:58-08:00
Duration: 2 min 4 s
Channel: Ivan Kochetkov
Description: lithium reacts spontaneously with bromine to produce lithium bromide if 250 g of lithium and 250 g of bromine are present at the beginning of the reaction determine the grams of libr produced 2 li b 2

          Lithium reacts spontaneously with bromine to produce lithium bromide.  If 25.0 g of lithium and 25.0 g of bromine are present at the beginning of the reaction, determine the grams of LiBr produced.  

2 Li + Br2 ? 2 LiBr

Added by Regina M.

Chemistry Matter and Change

Thandi Buthelezi, Laurel Dingrando,… 1st Edition

Chapter 11

Instant Answer

Solved by Expert Ivan Kochetkov

10/25/2021

Step 1

Given: Mass of lithium (Li) = 25.0 g Molar mass of lithium (Li) = 7.00 g/mol Mass of bromine (Br2) = 25.0 g Molar mass of bromine (Br2) = 160 g/mol Number of moles of lithium: \( \text{Moles of Li} = \frac{25.0 \, \text{g}}{7.00 \, \text{g/mol}} = 3.57 \, Show more…

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Lithium reacts spontaneously with bromine to produce lithium bromide. If 25.0 g of lithium and 25.0 g of bromine are present at the beginning of the reaction, determine the grams of LiBr produced. 2 Li + Br2 ? 2 LiBr