Question

End of chromosomal DNA 5' -------- 3' 3' -------- 5' The figure above represents the end of the DNA of a eukaryotic chromosome undergoing replication. The direction of replication is indicated by the arrow. a. Draw the new strands resulting from the replication process on the figure above. Indicate the 5' and 3' ends of each of your two strands. [Hint: The lagging stand must commence from an RNA primer. Indicate the location of the RNA primer that must be present for lagging strand synthesis] b. Removal of the RNA primer will be accomplished by ______ enzyme. Why is there a 'problem' following the removal of the primer? c. Assume that the end of the template of the lagging strand consists of TTAGGG repeats, many in a row, and ending with single stranded TTAGGG repeats at the end of the chromosomal DNA. If the RNA of Telomerase binds to the last 3 bases of a repeat and the sequence of the RNA includes a total of 9 bases, i.e., enough to provide a template of the repeat sequence, then what MUST the sequence of the RNA component of the telomerase be? d. Describe the subsequent steps by which telomerase will extend the repeats of the lagging strand. NOTE: Just to be clear......five replication processes discussed in lecture are: i. The initial opening up of DNA at the replication origin in Eukaryotes involving DnaA, SSBP, Helicase, and Gyrase. [Closed DNA -> Open DNA] ii. Maintenance and expansion of the fork including: SSBP, Helicase, and Gyrase (just sort of continue from the initial opening) iii. Leading strand synthesis: Primase & DNA Polymerase III iv. Lagging strand synthesis: Primase, DNA Pol III, DNA Pol I, ligase, repeatedly making and correcting short Okazaki fragments away from the fork. Refer to Q6-9 above. v. End replication problem for Eukaryotes 

          End of chromosomal DNA
5' -------- 3'
3' -------- 5'
The figure above represents the end of the DNA of a eukaryotic chromosome undergoing replication. The direction of replication is indicated by the arrow.
a. Draw the new strands resulting from the replication process on the figure above. Indicate the 5' and 3' ends of each of your two strands. [Hint: The lagging stand must commence from an RNA primer. Indicate the location of the RNA primer that must be present for lagging strand synthesis]
b. Removal of the RNA primer will be accomplished by ______ enzyme. Why is there a 'problem' following the removal of the primer?
c. Assume that the end of the template of the lagging strand consists of TTAGGG repeats, many in a row, and ending with single stranded TTAGGG repeats at the end of the chromosomal DNA. If the RNA of Telomerase binds to the last 3 bases of a repeat and the sequence of the RNA includes a total of 9 bases, i.e., enough to provide a template of the repeat sequence, then what MUST the sequence of the RNA component of the telomerase be?
d. Describe the subsequent steps by which telomerase will extend the repeats of the lagging strand.
NOTE: Just to be clear......five replication processes discussed in lecture are:
i. The initial opening up of DNA at the replication origin in Eukaryotes involving DnaA, SSBP, Helicase, and Gyrase. [Closed DNA -> Open DNA]
ii. Maintenance and expansion of the fork including: SSBP, Helicase, and Gyrase (just sort of continue from the initial opening)
iii. Leading strand synthesis: Primase & DNA Polymerase III
iv. Lagging strand synthesis: Primase, DNA Pol III, DNA Pol I, ligase, repeatedly making and correcting short Okazaki fragments away from the fork. Refer to Q6-9 above.
v. End replication problem for Eukaryotes
Show more…
End of chromosomal DNA 5' ——– 3' 3' ——– 5' The figure above represents the end of the DNA of a eukaryotic chromosome undergoing replication. The direction of replication is indicated by the arrow. a. Draw the new strands resulting from the replication process on the figure above. Indicate the 5' and 3' ends of each of your two strands. [Hint: The lagging stand must commence from an RNA primer. Indicate the location of the RNA primer that must be present for lagging strand synthesis] b. Removal of the RNA primer will be accomplished by enzyme. Why is there a 'problem' following the removal of the primer? c. Assume that the end of the template of the lagging strand consists of TTAGGG repeats, many in a row, and ending with single stranded TTAGGG repeats at the end of the chromosomal DNA. If the RNA of Telomerase binds to the last 3 bases of a repeat and the sequence of the RNA includes a total of 9 bases, i.e., enough to provide a template of the repeat sequence, then what MUST the sequence of the RNA component of the telomerase be? d. Describe the subsequent steps by which telomerase will extend the repeats of the lagging strand. NOTE: Just to be clear......five replication processes discussed in lecture are: i. The initial opening up of DNA at the replication origin in Eukaryotes involving DnaA, SSBP, Helicase, and Gyrase. [Closed DNA -> Open DNA] ii. Maintenance and expansion of the fork including: SSBP, Helicase, and Gyrase (just sort of continue from the initial opening) iii. Leading strand synthesis: Primase DNA Polymerase III iv. Lagging strand synthesis: Primase, DNA Pol III, DNA Pol I, ligase, repeatedly making and correcting short Okazaki fragments away from the fork. Refer to Q6-9 above. v. End replication problem for Eukaryotes

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Julianne Zedalis, John Eggebrecht
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Transcript

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00:01 Hello everyone, let's see our question.
00:03 So, our first question is based on the given figure which represents the end of dna of a eukaryotic chromosome undergoing replication.
00:13 Let's see.
00:14 So, question a.
00:19 Question a is, in this we have to draw the new strands resulting from the replication process on the given figure, indicating the 5 - and 3 -1 ends of each of your two strands.
00:33 Now let's draw this so we'll able to understand the replication process, the new strand which is resulted by the process of replication.
00:48 And here in this figure, rna primers are also going to get indicated.
01:02 So this different color, that is purple color i have used which is used to indicate rna primer.
01:12 So this is 5 -2 -3 -dage direction.
01:14 And this direction is 3 - to 5 -dash.
01:19 Let's see what will happen after replication.
01:32 So these are the fragments which are formed...
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