00:01
All right, so first we want to find the chiral centers of the molecule.
00:04
So for all the labeled carbons, basically, if you have a carbon that's chiral, it has to have four distinct groups.
00:11
So the central carbon of four regions, each with a bond, and then you'd have four different things around it, like so.
00:20
So we can't have anything that's part of a double bond because that's only three electron domains.
00:26
So we can cross out a and b.
00:27
We can't have anything that has, the hydrogens are not shown, but here there's only two bonds to the ring, so these are two hydrogens, meaning there's no distinct groups.
00:36
So that's not going to be a chiral center.
00:39
All right, for part, for d, we have two components of a ring where they're asymmetrical, and then we have this alkalal chain and then an unp pictured hydrogen coming out of the plane.
00:53
So yeah, this is going to be a chiral center.
00:55
E, like c, will have two h's.
00:58
And so will f, just to complete the octet, so those are not going to be chiral.
01:05
H is part of a double bond, and then i and k have at least two hydens, in this case three hydrants.
01:16
And then this one has three hydrogens as well...