Question

5) Express log(xy²z / x²) in terms of log x, log y, and log z. Given log? 2 = x, log? 5 = y, and log? 6 = z, express log? 0.15 in terms of x, y, and z. use 0.15 = 15/100 = (3x5)/(2x5x2x5) 6) Solve: a) 7^x = 83 b) 5^x = 0.3 c) 4^2x = 8^x+2 D) 5^x ? 43.2 E) log??(3 + x) = log?? x + 2 F) ln(5x - 2) = ln x + ln 4

          5)
Express log(xy²z / x²) in terms of log x, log y,
and log z.
Given log? 2 = x, log? 5 = y, and log? 6 = z,
express log? 0.15 in terms of x, y, and z. use 0.15 = 15/100 = (3x5)/(2x5x2x5)

6) Solve:
a) 7^x = 83
b) 5^x = 0.3
c) 4^2x = 8^x+2

D) 5^x ? 43.2

E) log??(3 + x) = log?? x + 2
F) ln(5x - 2) = ln x + ln 4

5)
Express log(xy²z / x²) in terms of log x, log y,
and log z.
Given log? 2 = x, log? 5 = y, and log? 6 = z,
express log? 0.15 in terms of x, y, and z. use 0.15 = 15/100 = (3x5)/(2x5x2x5)

6) Solve:
a) 7^x = 83
b) 5^x = 0.3
c) 4^2x = 8^x+2

D) 5^x ? 43.2

E) log??(3 + x) = log?? x + 2
F) ln(5x - 2) = ln x + ln 4

Added by Luis B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

12/03/2023

Step 1

log 5) xy'z = log 5) x + log 5) y' + log 5) z Since log 5) y' is the logarithm of the reciprocal of y, we can rewrite it as: log 5) y' = -log 5) y So the expression becomes: log 5) xy'z = log 5) x - log 5) y + log 5) z Show more…

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5) Express log(xy²z/x²) in terms of log x, log y, and log z. Given log_a 2 = x, log_a 5 = y, and log_a 6 = z, express log_a 0.15 in terms of x, y, and z. use 0.15 = 15/100 = (3x5)/(2x5x2x5) 6) Solve: a) 7^x = 83 b) 5^x = 0.3 c) 4^2x = 8^x+2 D) 5^x ≥ 43.2 E) log_10(3 + x) = log_10 x + 2 F) ln(5x - 2) = ln x + ln 4