00:01
Dear students, these are the elements of the second period of the periodic table and we have to find out which element has the highest second ionization energy and which element has the lowest second ionization energy.
00:14
Let us write the electronic compression of these elements, lithium 1 s2, 2 s1, beryllium 1 s2 2 s2, boron 1s2, 2s2 to p1, then carbon, 1 s2 2 s 2p 2 nitrogen 1 s 2 s 2p 3 then oxygen 1 s 2 s 2 s 2 p 4 fluorine 1 s 2 s 2 p 5 and neon 1 s 2 s 2p 6 now after losing 1 electron the electronic configuration will be i am writing the valence cell this is the valence cell configuration.
01:05
Now let us write the valence cell configuration after losing one electron.
01:09
It will be here.
01:11
Here it will become 2 s 0.
01:14
So the electronic compression will be 1 s 2, 2 s 0.
01:19
In beryllium it is valent cell compression is 2 s1.
01:23
Here it is boron it is 2s2, carbon 2s2 to p1, then comes nitrogen, 2 s2 to p p2, oxygen, 2 s2, 2p3, fluorine, 2s2, 2p4, neon, 2s2 to p5.
01:45
Now if we see the electronic confessions of the monopositive ions, beryllium clearly shows that it has one electron in the valent cell.
01:56
Now if it loses one electron, then for to form the dipositive ion, then its confration will be 1s2...