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Make the given substitution to evaluate the indefinite integral.\\ $\int 14\csc^2(7x)\cot(7x)dx$, a. $u = \cot(7x)$, b. $u = \csc(7x)$\\ a. Using $u = \cot(7x)$, $\int 14\csc^2(7x)\cot(7x)dx = -\cot^2(7x) + c$\\ b. Using $u = \csc(7x)$, $\int 14\csc^2(7x)\cot(7x)dx = $

          Make the given substitution to evaluate the indefinite integral.\\
$\int 14\csc^2(7x)\cot(7x)dx$, a. $u = \cot(7x)$, b. $u = \csc(7x)$\\
a. Using $u = \cot(7x)$, $\int 14\csc^2(7x)\cot(7x)dx = -\cot^2(7x) + c$\\
b. Using $u = \csc(7x)$, $\int 14\csc^2(7x)\cot(7x)dx = $

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Make the given substitution to evaluate the indefinite integral.

∫ 14csc^2(7x)cot(7x)dx, a. u = cot(7x), b. u = csc(7x)

a. Using u = cot(7x), ∫ 14csc^2(7x)cot(7x)dx = -cot^2(7x) + c

b. Using u = csc(7x), ∫ 14csc^2(7x)cot(7x)dx =

Added by Peter G.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Adi S

07/18/2023

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We have du = -csc^2(7x)dx. Show more…

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Make the given substitution to evaluate the indefinite integral. a.Using u=cot7x14csc27xcot7xdx=-cot27x+c b.Using u=csc7x,14csc27xcot7xdx=

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