Mass m1 on the frictionless table of the figure is connected by a string through a hole in the table to a hanging mass m2. (Figure 1) With what speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?
Added by Amy K.
Step 1
This means the tension force in the string must be equal to the weight of m2. Therefore, T = m2 * g. Show more…
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Mass $m_{1}$ on the frictionless table of FIGURE P8.46 is connected by a string through a hole in the table to a hanging mass $m_{2},$ With what speed must $m_{1}$ rotate in a circle of radius $r$ if $m_{2}$ is to remain hanging at rest? (FIGURE CAN'T COPY)
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