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Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by $f(x) = -3x + 31$ and $g(x) = 3x - 23$ on the interval $[6, 12]$. Area =

          Math 110 Course Resources
- Applications of Definite Integrals Course Packet on the area between two curves
Determine the area of the region bounded by $f(x) = -3x + 31$ and $g(x) = 3x - 23$ on the interval $[6, 12]$.
Area =
        
Math 110 Course Resources
- Applications of Definite Integrals Course Packet on the area between two curves
Determine the area of the region bounded by f(x) = -3x + 31 and g(x) = 3x - 23 on the interval [6, 12].
Area =

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Math 110 Course Resources: Applications of Definite Integrals Course Packet on the Area Between Two Curves Determine the area of the region bounded by f(x) = -3x + 31 and g(x) = 3x - 23 on the interval [6, 12]. Area =
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Transcript

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00:01 Hi, now we are going to find the area of the region bounded by y is equal to x minus 1 into e power 5 x squared minus 10 x and y is equal to 0 in the interval closed 0 comma 2.
00:19 Now i have to equate the given y values then we get x minus 1 into e power 5 x squared minus 10 x is equal to 0.
00:32 From this we get x minus 1 is equal to 0.
00:36 So we have the value of x is equal to 1.
00:40 Then we know that the area a is equal to integral over a2b, f of x into dx.
00:51 Now here the given interval is closed 0 comma 2.
00:55 So the limit of the integration will be 0 to 1 .1...
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