%H in H2O2=(2(1.008 amu))/(2(1.008 amu)+2(16.00 amu))× 100=

Name: %H in H2O2=(2(1.008 amu))/(2(1.008 amu)+2(16.00 amu))× 100=
Uploaded: 2024-10-04T04:00:16-08:00
Duration: 1 min 24 s
Channel: Numerade
Description: %H in H2O2=(2(1.008 amu))/(2(1.008 amu)+2(16.00 amu))× 100=

Question

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Question

\( \% \mathrm{H} \) in \( \mathrm{H}_{2} \mathrm{O}_{2}=\frac{2(1.008 \mathrm{amu})}{2(1.008 \mathrm{amu})+2(16.00 \mathrm{amu})} \times 100= \)

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