Question

speed of $v_0$ at an angle A to the horizontal are given by $h(t) = v_0t \sin A - 0.5 \, g t^2$ $v(t) = \sqrt{v_0^2 - 2v_0 \, gt \sin A + g^2 t^2}$ where g is the acceleration due to gravity. The projectile will strike the ground when $h(t) = 0$, which gives the time to hit $t_{hit} = 2(v_0/g)\sin A$. Suppose that $A = 40^\circ$, $v_0 = 35 \text{ m/s}$, and $g = 9.81 \text{ m/s}^2$. Use the MATLAB relational and logical operators to find the times when a. The height is no less than 18 m. b. The height is no less than 10 m and the speed is simultaneously no greater than 30 m/s.

          speed of $v_0$ at an angle A to the horizontal are given by

$h(t) = v_0t \sin A - 0.5 \, g t^2$

$v(t) = \sqrt{v_0^2 - 2v_0 \, gt \sin A + g^2 t^2}$

where g is the acceleration due to gravity. The projectile will strike the ground
when $h(t) = 0$, which gives the time to hit $t_{hit} = 2(v_0/g)\sin A$.
Suppose that $A = 40^\circ$, $v_0 = 35 \text{ m/s}$, and $g = 9.81 \text{ m/s}^2$. Use the MATLAB
relational and logical operators to find the times when
a. The height is no less than 18 m.
b. The height is no less than 10 m and the speed is simultaneously no greater
than 30 m/s.

Show more…

speed of v0 at an angle A to the horizontal are given by

h(t) = v0t sin A - 0.5 g t^2

v(t) = √(v0^2 - 2v0 gt sin A + g^2 t^2)

where g is the acceleration due to gravity. The projectile will strike the ground
when h(t) = 0, which gives the time to hit thit = 2(v0/g)sin A.
Suppose that A = 40^∘, v0 = 35 m/s, and g = 9.81 m/s^2. Use the MATLAB
relational and logical operators to find the times when
a. The height is no less than 18 m.
b. The height is no less than 10 m and the speed is simultaneously no greater
than 30 m/s.

Added by Stanley V.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Stephen Zaffke

Step 1

5 * g * t^2 and solve for t. 18 = v0 * sin(A) - 0.5 * g * t^2 We can rearrange the equation to solve for t: 0.5 * g * t^2 = v0 * sin(A) - 18 t^2 = (2 * (v0 * sin(A) - 18)) / g t = sqrt((2 * (v0 * sin(A) - 18)) / g) Now we can substitute the given values A = Show more…

Show all steps

lock

Thanks for your feedback!

MATLAB Help The speed of an object at an angle A to the horizontal is given by: ht = v0 * sin(A) - 0.5 * g * t^2 v = v0 - 2 * vo * g * t * sin(A) + g^2 * t^2 where g is the acceleration due to gravity. The projectile will strike the ground when h = 0, which gives the time to hit thit = 2 * vo / (g * sin(A)). Suppose that A = 40, vo = 35 m/s, and g = 9.81 m/s^2. Use the MATLAB relational and logical operators to find the times when: a. The height is no less than 18 m. b. The height is no less than 10 m and the speed is simultaneously no greater than 30 m/s.

Play audio

Feedback

Powered by NumerAI

Stephen Zaffke and 89 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later