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The maximum distance S and the maximum height h that a projectile shot at an angle heta are given by: egin{itemize} item $s = frac{(v_0)^2}{g} sin(2 heta)$ and $h = frac{(v_0)^2 (sin( heta))^2}{2g}$ item where $v_0$ is the shooting velocity and $g = 9.8 ext{ m/s}^2$ end{itemize} a) Create a user-defined MATLAB function called projectile to determine s and h. Hint: The inputs of the function are $v_0$ and $ heta$ and the outputs are S & h. b) Use the previous function to determine s and h for $ heta = 15^circ$ and $v_0 = 260 ext{ m/s}$.

          The maximum distance S and the maximum height h that a projectile shot at an angle 	heta are
given by:
egin{itemize}
    item $s = frac{(v_0)^2}{g} sin(2	heta)$ and $h = frac{(v_0)^2 (sin(	heta))^2}{2g}$
    item where $v_0$ is the shooting velocity and $g = 9.8 	ext{ m/s}^2$
end{itemize}
a) Create a user-defined MATLAB function called projectile to determine s and h.
Hint: The inputs of the function are $v_0$ and $	heta$ and the outputs are S & h.
b) Use the previous function to determine s and h for $	heta = 15^circ$ and $v_0 = 260 	ext{ m/s}$.

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$The maximum distance S and the maximum height h that a projectile shot at an angle heta are given by: eginitemize item s = frac(v0)^2g sin(2 heta) and h = frac(v0)^2 (sin( heta))^22g item where v0 is the shooting velocity and g = 9.8 ext m/s^2 enditemize a) Create a user-defined MATLAB function called projectile to determine s and h. Hint: The inputs of the function are v0 and heta and the outputs are S h. b) Use the previous function to determine s and h for heta = 15^circ and v0 = 260 ext m/s.$

Added by David H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

10/11/2022

Step 1

81 \, m/s^2 \) and \( V_0 = 216 \, m/s \). ** Show more…

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The maximum distance s and the maximum height h that a projectile shot at an angle ̘ are given by: s = (v0^2 / g) * sin(2̘) and h = (v0^2 * (sin(̘))^2) / 2g, where v0 is the shooting velocity and g = 9.8 m/s^2. Create a user-defined MATLAB function called projectile to determine s and h. Hint: The inputs of the function are v0 and ̘ and the outputs are S & h. Use the previous function to determine s and h for ̘ = 15° and v0 = 260 m/s.

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Transcript

00:01 Declaration of constance so percentage declaration of constants is given to us where the value of it is given which is 9 .81 and the value of v node is given which is 260 so from here we can write as percentage declare d - theta value as a range so value as a range and the range is given which is theta is equal to 15 ratio 10 ratio 75 so, since percentage, since matlab will take angle in radiance, will take angle in radiance.

00:44 So, so convert into radiance, theta, radiant is equal to theta star pi divided by 180 degree.

00:57 So from here, we can write it as percentage set the number of a number of a number.

01:04 Values to be number of values to be generated.

01:12 So from here we can write it as lan is equal to 7 and again the percentage for loop to computed are to compute the s and h values is for i and i is given which is equal to one ratio 1 n.

01:33 So from here we can write it as the percentage calculated and prompt the value of s value.

01:46 And from here we can write it as s is equal to v0 star v0, star, sine multiple.

01:53 We can say that 2 multiply theta red 1 divided by g.

01:59 So from here we can percentage calculate and prompt the s value.

02:08 So we can write it as h is equal to v -note multiply by v -note, multiply by sine theta -red -i, multiply by sine theta red i divided by 2g so this is the complete solution or we can say the formula for that now we have to compute the output so for computing the output we can write as so for computing the output we can write it so for computing the output we can write it as the result is of scientific notations so that this is comes out in the terms of 3 .44 -5 -4 -638 -1 -2 -e plus 0 .03 which means 3 .44 -563 -8124 -36 -289.

03:27 By 10 to the power 3...

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