Mesitylene, a hydrocarbon found in crude oil, has an empirical formula of C3H4 and an experimentally determined molecularweight of 121 amu. What is its molecular formula?
Added by Ashley P.
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01 g/mol) + (4 x 1.01 g/mol) Molar mass = 36.03 g/mol + 4.04 g/mol Molar mass = 40.04 g/mol Show more…
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Mesitylene is a liquid hydrocarbon. If $0.115 \mathrm{~g}$ of the compound is burned in pure $\mathrm{O}_{2}$ to give $0.379 \mathrm{~g} \mathrm{CO}_{2}$ and $0.1035 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}$, what is the empirical formula of the compound?
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