The atmospheric pressure at a height of x meters above sea level is $P(x) = 10^4e^{-0.00012x}$ kilograms per square meter. What is the rate of change of the pressure with respect to the height at $x = 220$ m? At $x = 440$ m? Round each answer to two decimal places. $P'(220) =$ $P'(440) = $
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P'(x) = -0.00012 * 10^(4) * e^(-0.00012x) Show more…
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