7. Methanol (CH3OH) burns according to the equation 2CH3OH(l) + 3O2(g) ? 2CO2(g) + 4H2O(l), ?H = -1454 kJ/mol. If 750 kJ of heat is produced, what mass of methanol is burned? 750 kJ %% (2 mol / -1454 kJ) %% (32.042 g / 1 mol) = -33.06 g C- 12.01 H3- 3.024 O- 16.00 H- 1.008 24031.5 / -2908
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First, we need to find out how many moles of methanol are burned to produce 750 kJ of heat. We know that -1454 kJ of heat is produced per mole of methanol burned. So, we can set up a proportion: (750 kJ) / (x moles) = (-1454 kJ) / (1 mole) Show more…
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