Methanol undergoes combustion according to the equation. Find the amount of heat given off from the combustion of 64 g CH3OH (methanol). (MM = 32 g/mol) (AH = -1452.8 kJ) 2 CH3OH + 3 O2 -> 3 2 CO2 + 4 H2O a. -2905.6 kJ b. -2179.2 kJ c. -1452.8 kJ d. -726.4 kJ
Added by Joseph E.
Step 1
Number of moles = Mass / Molar mass Number of moles = 64 g / 32 g/mol Number of moles = 2 moles Show more…
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