Question

Minimize $C = 150x + 650y$ subject to $40x + 120y \ge 3,919$ $45x + 255y \ge 6,930$ Number of hours to run line 1 is Number of hours to run line 2 is Minimum cost is $

Name: minimize c 150x 650y subject to 40x 120y ge 3919 45x 255y ge 6930 number of hours to run line 1 is number of hours to run line 2 is minimum cost is 31985
Uploaded: 2022-07-29T20:50:32-08:00
Duration: 1 min 27 s
Channel: Andrew Noble
Description: minimize c 150x 650y subject to 40x 120y ge 3919 45x 255y ge 6930 number of hours to run line 1 is number of hours to run line 2 is minimum cost is 31985

          Minimize  $C = 150x + 650y$ subject to
$40x + 120y \ge 3,919$
$45x + 255y \ge 6,930$
Number of hours to run line 1 is 
Number of hours to run line 2 is 
Minimum cost is $

minimize c 150x 650y subject to 40x 120y ge 3919 45x 255y ge 6930 number of hours to run line 1 is number of hours to run line 2 is minimum cost is 31985

Added by M-Nica C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Noble

07/29/2022

Step 1

Step 1: The objective function is to minimize the cost, which is represented by the equation $C = 150x + 650y$, where x is the number of hours line 1 runs and y is the number of hours line 2 runs. Show more…

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Minimize $C = 150x + 650y$ subject to $40x + 120y \ge 3,919$ $45x + 255y \ge 6,930$ Number of hours to run line 1 is Number of hours to run line 2 is Minimum cost is $