00:04
Now here you have misa, right, it's fired from gwan level with initial velocity given here, right? and the engine shut off after launch.
00:13
And if the external force, it's the only gravitational force, what is you found, trajectory of the mesa, right? so the trajectory of mesa, rt, obviously, is given by.
00:23
You know, the only the x and y directions, they are just a free motion, right? i mean, just the free motion.
00:29
So they're just uniform, i mean, they just move uniformly, right? a constant velocity.
00:34
So the positions, of course, in the x and y direction, where we just proportion to multiply by t, right, and 1 -2 -0 -0 -t.
00:44
And in the z direction, you would have different, right, because of the gravity.
00:50
So you would have 352t and minus the gt squared over 2, right? now, g is given by the question here, right? so that would be the expression...