00:02
So in the house mouse, the series of allele of a single gene effect the coat color.
00:07
There are five different alleles.
00:09
There are a .y, yellow, dominant over al agouti and light belli, dominant over agouti by itself.
00:17
And then dominant over black and tan.
00:20
And last one is black.
00:22
So the dominance is complete.
00:24
So we want to figure out the phenotype expected from each of the cross following.
00:29
So let's take a look at the first cross.
00:31
So the first cross is a plus lower a cross with al with capital a.
00:40
So for each parent, it will produce two possible allios.
00:43
The two alleles separate.
00:45
Each has 50 % of the chance.
00:49
So let's see there are four different alleles.
00:52
And then we do our punday square, a plus a, a, l, and capital a.
01:05
So in the next generation, you put the two allio back.
01:07
Together then we decide the phenotype by looking at the dominance so you have four different genotype a l a plus we know that a l is dominant over a plus completely so it's going to be a a goody and light belly and the other one same thing a l and a again a goody light is dominant, so this is the same phenotype, agouti and light.
01:54
So the bottom two, they both have a dominant capital a.
02:01
So the capital a is going to be dominant over a plus an a, so both of them will equal capital a, which is just agouti.
02:13
So in this case, half of the offspring will be a goody in line, the other half will be a goody just by itself.
02:23
The second cross a capital a and lower a plus and a y and lower a so again you have two alleles from each of the parent and we're going to repeat the same process of honey square capital a a plus a y and lower a again we put the two allio okay, so in this case you can tell the first two, a, y, capital a, and a, y, a plus.
03:37
In both case, you have a y, so ay, yellow is dominant over both capital a and a plus.
03:45
Both of them will be yellow...