00:01
Got a quick stoichiometry and experimental design problem.
00:06
So we are reacting acetylphenone with phenyl magnesium bromide, a one molar solution of it in thf, and then doing acidic workup to give us this alcohol, which is 1 -1 diphenyl ethanol.
00:20
And so first we need to determine the amounts of reagents.
00:25
So the mass of acetophenone or a and the volume of the phenomagene bromide.
00:31
If we're using 1 .5 millimolars with a 10 % excess of our grignior.
00:37
So we have acetyophenone, which has a mass of about 120 grams per mole, and we are using 0 .0015 moles.
00:57
And so that is going to be about 180 milligrams of acetophenone that we're going to be using.
01:09
And next we want to determine how much of the greenyard that we're going to be using.
01:15
And so we have a 10 % excess, which means that we're going to be using 1 .65 millimoles of the greenyard.
01:24
I'll just label that g.
01:26
And so that's a one molar solution in thf.
01:31
And so this is pretty easy to do.
01:35
We can just multiply that.
01:38
We can just divide that by the molarity, which if we convert it to millimolers, it's a thousand millimolars, or we can actually just convert this into moles, so 0 .00165 moles of the grignard, so that would be 0 .00165 liters or 1 .65 milliliters of our grignard...