00:01
Okay, so for this problem, we are provided a balanced chemical reaction and we're asked if we have to produce 0 .75 grams of nacl, how would we go about that? how many grams of n82 -c -o -3 would we need? so first off, we need to recognize that gram -to -gram is a three -step conversion.
00:20
The second thing is we need to figure out what those three steps are going to be.
00:24
So first we always start by writing what we know, which is 0 .75 grams of nacl.
00:33
The first step is always to get rid of what we started with.
00:36
So if we start with grams of nicl, grams of nacl needs to go on the bottom.
00:41
And the only thing that can go with grams is one mole of that same substance.
00:48
To find grams, we go to the periodic table and add them up.
00:53
So n .a has a molar mass of 22 .99.
00:58
Cl has a molar mass of 35 .45.
01:01
Since there is only one of each, we just add those up.
01:05
And when we get the mass, it is 58 .44.
01:10
So that is step one.
01:12
Step two then is to get rid of those moles of nacl.
01:15
So moles of nacl will be on the bottom.
01:19
Remember, we're trying to get to n82 -c -o -3.
01:21
However, we can't go straight there yet.
01:23
Instead, we're going to go to moles of n -a -2 -c -o -3.
01:29
So when we have moles on top of moles, we have to look up at our balanced chemical reaction and look at the coefficients.
01:35
So n -a -2 -c -o -3 does not have a coefficient, therefore it is 1.
01:39
N -a -cl, however, it does have a coefficient, so it is 2.
01:43
We write a 2 down by the nicl...