0:00
Hello.
00:01
So in this question we are given that is the volume of n .a .2 .s .3.
00:13
That is v1 is equal to 35 ml.
00:18
And that will be equal to 35 multiply by 10 days to the power minus 3 liter.
00:23
We can write it as.
00:25
And the molarity of n .a2 .s .3, it is given 0 .0 .7 .7.
00:33
776 m it is given and we need to find out the mass of solution.
00:49
So from these two given information we can find out the number of moles of na2 -so3 which is equal to m multiply by v or m1 v1 this is m1 we can say so m it is 0 .0 7 7 multiplied by v it is given 35 multiplied by 10 to the power minus 3 and this will become 2 .72 multiply by 10 raised to the power minus 3 moles for n -a2 so3 now we are given the reaction that is n -a2 so3 plus 2hclo4 it produced 2naclo4 plus 2h2o plus so2.
01:47
As we can see here that 1 mole of na2so3, it requires 2 mole of hclo4 or it reacts with the 2 mole of hcl4.
02:08
So therefore the number of moles of hclo3 needed for complete the reaction.
02:16
Have here 2 .72 multiply by 10 to the power minus 3, na2 so3 requires 2 multiply by 2 .72 multiply by 10 to the power minus 3.
02:33
That is 5 .44 multiplied by 10 days to the power minus 3 moles of hclo 4.
02:42
So this much of moles of hclo 4 is required for complete the reaction.
02:48
Also we know that that is the molar mass of hcl of 4, it is 100 .5 gram per mole.
03:00
Now we have the number of moles, we have the molar mass...