00:01
In this video, we are going to name the following branched alkan using iupac nomenclature rules.
00:07
So the rule is that we have to find the longest continuous carbon chain.
00:13
So let's see.
00:14
If we do 1, 2, 3, 4, 5, 6, 7, 8, or if this is 5, 6, 7, 8, 9, it looks like if we take this chain like so, where like if i took this branch it's the same as this one and this one is the same as this one so it doesn't run that looks like it's the continuous carbon the longest continuous carbon chain now to have the lowest numbered substituents if this is a one then we'll have two four five six and seven um if this is the one then the substituents would start at three so we'll number it this way because that will give us the lowest number of substituents the lowest numbers on the substituents all right so this is a methyl group because it has one carbon.
01:24
This is also a methyl group.
01:27
This has one, two, three carbon, so it's propyl.
01:32
This has two carbon, so it's ethyl, and then this is ethyl...