00:01
Name the following cycloycines.
00:06
A.
00:08
We number carbons in the ring to assign the lowest number to the double bond.
00:15
So it's three, methyl, one cyclohexine, the six carbons in the ring.
00:25
B, there are five carbons in the ring and a double barn.
00:29
So it's cyclopentin.
00:31
We number the ring to assign the smallest number to the bond and also smallest numbers to the substituents.
00:43
So you have a double bond in position 1 and 2 method groups in positions 2 and 3.
00:55
C.
00:56
There are 4 carbons in the ring and 2 double bonds, so it's cyclobuta -dain.
01:04
We number the rings to assign the smallest numbers to the double bonds.
01:13
So it's 1 3, cyclobuta -dine, and the smallest number to the substituent, ethyl.
01:23
It's at carbon 1...