Naval intelligence reports that 10 enemy vessels in a fleet of 21 are carrying nuclear weapons. If 7 vessels are randomly targeted and destroyed, what is the probability that more than 1 vessel transporting nuclear weapons was destroyed? Express your answer as a fraction or a decimal number rounded to four decimal places.
Added by Silvia C.
Step 1
This can be calculated using combinations, denoted as C(n, k) or "n choose k", which is equal to n! / (k!(n-k)!), where n is the total number of items and k is the number of items to choose. In this case, n = 21 and k = 7, so the total number of ways to choose 7 Show more…
Show all steps
Close
Your feedback will help us improve your experience
Hoan Nguyen and 61 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Naval intelligence reports that 8 enemy vessels in a fleet of 22 are carrying nuclear weapons. If 7 vessels are randomly targeted and destroyed, what is the probability that no more than 1 vessel transporting nuclear weapons was destroyed? Express your answer as a fraction or a decimal number rounded to four decimal places.
Audrey F.
Naval intelligence reports that 9 enemy vessels in a fleet of 21 are carrying nuclear weapons. If 5 vessels are randomly targeted and destroyed, what is the probability that less than 4 vessels transporting nuclear weapons were destroyed? Express your answer as a fraction or a decimal number rounded to four decimal places.
Robin C.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD