Naval intelligence reports that 8 enemy vessels in a fleet of 22 are carrying nuclear weapons. If 7 vessels are randomly targeted and destroyed, what is the probability that no more than 1 vessel transporting nuclear weapons was destroyed? Express your answer as a fraction or a decimal number rounded to four decimal places.
Added by Robert J.
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Step 1:** Calculate the probability of X = 0 (no vessels carrying nuclear weapons were destroyed): \[P(X=0) = \binom{7}{0} \left(\frac{8}{22}\right)^0 \left(\frac{14}{22}\right)^7\] ** Show more…
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