Question

nd parametric equations for the line through (-6,5, -7) perpendicular to the plane 9x + 5y + 3z = 22. z = -7 + 3t. \boxed{} , y = \boxed{}, z = -7 + 3t, -\infty < t < \infty pe expressions using t as the variable.)

          nd parametric equations for the line through (-6,5, -7) perpendicular to the plane 9x + 5y + 3z = 22.
z = -7 + 3t.
\boxed{} , y = \boxed{}, z = -7 + 3t, -\infty < t < \infty
pe expressions using t as the variable.)

nd parametric equations for the line through (-6,5, -7) perpendicular to the plane 9x + 5y + 3z = 22.
z = -7 + 3t.
, y = , z = -7 + 3t, -∞< t < ∞pe expressions using t as the variable.)

Added by Grant C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Naksha G

03/02/2022

Step 1

The coefficients of x, y, and z in the equation of the plane represent the components of the normal vector. So, the normal vector is <9, 5, 3>. Show more…

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nd parametric equations for the line through (-6,5,-7) perpendicular to the plane 9x+5y+3z=22. z=-7+3t ty=,z=-7+3t,-infty pe expressions using t as the variable. nd parametric equations for the line through (- 6,5, - 7) perpendicular to the plane 9x + 5y + 3z=22 z=-7+3t. y=z=-7+3t,-<t< oe expressions using t as the variable.