need help with d 2for the following voftaic cell at298 k in which the rcaction is bebesbr acalcu

Here we have to choose the anode and the cathode, which would have the standard potential of 1 .

Question

Need help with D! For the following voltaic cell at 298 K, in which the reaction is (Be+BeS+Br), calculate the cell potential (E) under standard conditions: Ce(aq) + e -> Ce(aq) E = +1.6 V Cy(aq) + 3C(s) E = -0.74 V Eo = E(cathode) - E(anode) Eo = 1.6 V - (-0.74 V) Eo = 2.34 V (a) Calculate E when [Ce] = 3.0 M, [Cc] = 0.10 M, and [Cr] = 0.010 M: 3Ce4+ (aq) + Cr(s) -> 3Cc3+ (aq) + Cr3+ (aq) E = 0.10 V - 0.010 V E = 0.090 V (b) Determine G (under standard conditions): G = -nFE G = -3 mol x 46500 C/mol x 2.34 V G = -323,130 J = -323.13 kJ (c) Determine G under the same conditions as in part b.

          Need help with D!

For the following voltaic cell at 298 K, in which the reaction is (Be+BeS+Br), calculate the cell potential (E) under standard conditions:
Ce(aq) + e -> Ce(aq) E = +1.6 V
Cy(aq) + 3C(s) E = -0.74 V

Eo = E(cathode) - E(anode)
Eo = 1.6 V - (-0.74 V)
Eo = 2.34 V

(a) Calculate E when [Ce] = 3.0 M, [Cc] = 0.10 M, and [Cr] = 0.010 M:
3Ce4+ (aq) + Cr(s) -> 3Cc3+ (aq) + Cr3+ (aq)
E = 0.10 V - 0.010 V
E = 0.090 V

(b) Determine G (under standard conditions):
G = -nFE
G = -3 mol x 46500 C/mol x 2.34 V
G = -323,130 J = -323.13 kJ

(c) Determine G under the same conditions as in part b.

need help with d 2for the following voftaic cell at298 k in which the rcaction is bebesbr acalculate the cell potential eunder standard conditions ceaqeceaqe16iv cyaq3ccnse 074v eoleecathade 89127

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