Question

Enter the global maximum and global minimum values for p(x) = 10 x^6 + 36 x^5 - 75 x^4 - 540 x^3 - 960 x^2 - 720 x over the interval [-4, 4] in the boxes below. Global maximum value: 54000 Global minimum value: -15417 To prevent typing errors, you can copy and paste p:= 10x^6+36x^5-75x^4-540x^3-960x^2-720x; in your Maple window.

          Enter the global maximum and global minimum values for
p(x) = 10 x^6 + 36 x^5 - 75 x^4 - 540 x^3 - 960 x^2 - 720 x
over the interval [-4, 4] in the boxes below.
Global maximum value: 54000
Global minimum value: -15417
To prevent typing errors, you can copy and paste
p:= 10*x^6+36*x^5-75*x^4-540*x^3-960*x^2-720*x;
in your Maple window.

Enter the global maximum and global minimum values for
p(x) = 10 x^6 + 36 x^5 - 75 x^4 - 540 x^3 - 960 x^2 - 720 x
over the interval [-4, 4] in the boxes below.
Global maximum value: 54000
Global minimum value: -15417
To prevent typing errors, you can copy and paste
p:= 10*x^6+36*x^5-75*x^4-540*x^3-960*x^2-720*x;
in your Maple window.

Added by Jane F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Shaiju T

05/05/2022

Step 1

To find the critical points, we need to find the values of x where the derivative of p(x) is equal to zero or undefined. First, let's find the derivative of p(x): p'(x) = 60x^5 + 180x^4 - 300x^3 - 1638x^2 - 1920x - 720 Now, let's set p'(x) equal to zero and Show more…

Show all steps

Thanks for your feedback!

Need help with the global max. Enter the global maximum and global minimum values for p(x)=10 x6+36 x5-75x4-540x3-960 x2-720x over the interval 4, 4 in the boxes below Global maximum value: 54000 Global minimum value: -15417 To prevent typing errors,you can copy and paste p:= 10*x^6+36*x^5-75*x^4-546*x^3-960*x^2-720*x; in your Maple window