Question

The cylinder has radius $r = 0.1 \text{ m}$ and mass $m = 44 \text{ kg}$. Determine the mass moment of inertia in $\text{kg} \cdot \text{m}^2$ and the radius of gyration in millimeters of the cylinder about an axis through point O directed perpendicular to the plane of the page $I_O = \text{________} \text{ kg} \cdot \text{m}^2$ $k_O = \text{________} \text{ mm}$

          The cylinder has radius $r = 0.1 \text{ m}$ and mass $m = 44 \text{ kg}$.
Determine the mass moment of inertia in $\text{kg} \cdot \text{m}^2$ and the radius of gyration in millimeters of the cylinder about an axis through point O directed perpendicular to the plane of the page
$I_O = \text{________} \text{ kg} \cdot \text{m}^2$
$k_O = \text{________} \text{ mm}$

The cylinder has radius r = 0.1 m and mass m = 44 kg.
Determine the mass moment of inertia in kg·m^2 and the radius of gyration in millimeters of the cylinder about an axis through point O directed perpendicular to the plane of the page
IO = kg·m^2
kO = mm

Added by Victor R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dinesh Chand Jangid

Step 1

The formula for the mass moment of inertia of a solid cylinder is given by: I = (1/2) * m * r^2 where I is the mass moment of inertia, m is the mass of the cylinder, and r is the radius of the cylinder. Plugging in the given values, we have: I = (1/2) * 44 kg Show more…

Show all steps

Thanks for your feedback!

The cylinder has radius r = 0.1 m and mass m = 44 kg. Determine the mass moment of inertia in kgÂ·m^2 and the radius of gyration in millimeters of the cylinder about kgÂ·m^2Â·mm.