SORU 26 The pump shown in Fig. 4 adds a 15-ft head to the water ($\rho$ = 1.94 slugs/ft$^3$, $\mu$ = 2.34 × 10$^{-5}$ lbf-s/ft$^2$ and $\gamma$= 62.4 lbf/ft$^3$) being pumped from the upper tank to the lower tank. If the pipe has a roughness $\epsilon$ = 0.003 ft, determine the flow rate Q. Use $f$ = 0.03 as the initial guess then the following equation for the remaining iterations until $f$ converges to the thousandth decimal place. (Note: 1 psi = 144 lbf/ft$^2$ and g = 32.2 ft/s$^2$) $\frac{1}{\sqrt{f}}$ = -1.8 log$\left[\frac{\epsilon/(D)}{3.7} + \frac{6.9}{Re}\right]$
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A water pump is used to pump water from one large reservoir to another reservoir that is at a higher elevation. The free surfaces of both reservoirs are exposed to the atmospheric pressure, as sketched in Fig. P14-39. The dimensions and loss coefficients are provided in the figure. Determine the pump power required if the volumetric flow rate is 10 Lpm. If the pump's efficiency is 85%, determine the power required to drive the pump. If the pump's performance is given by Havailable = H0 - aV-dot^2, where a = 0.0678 m/(Lpm)^2, and the Hrequired equals the Havailable, determine the shutoff head H0.
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