00:01
The cdf, the cumulative distribution function, was given here.
00:05
So the function was, let me just write the function, which is x squared over 16, and the value is the x variable is between 0 and 4.
00:15
So in part a, what we have to find, we have to find the probability of 1 less than x, less than, this is 3, which is equal to.
00:23
This is the integral of this function, and the interval was from 1 to 3.
00:29
Let's get the value.
00:31
This is one, three, the function here, x square over 16 dx.
00:35
Let's take the integral.
00:36
This is x cubed over 48 from 1 to 3.
00:40
Just plug in 3.
00:42
28 over 48 minus 1 over 48, which is equal to 26 over 48.
00:48
If i simplify by 2, 13 over 24 is the answer for part 8.
00:56
What about 2i? so we have to get the mean of the random variable here.
01:01
Remember the formula, the mean, which is also equal to the expected value, that is equal to x times f of x and dx.
01:10
And the intervals, let's say this is a and b.
01:13
So the mean score, which is equal to, so the interval is from 0 to 4, so the variable is x.
01:20
And we have x squared over 16 the function.
01:23
And let's put the dx here, which is.
01:26
So from 0 to 4, this is x cubed over 16 dx.
01:31
Let's take the integral.
01:33
This is x to the power of 4 over 64 and 0 and 4.
01:37
If i plug in the values here, this is 4 to the power 4 divided by.
01:41
This is, let's say, 4 cubed minus 0, which is equal to 4.
01:45
This is the expected value that we have for the question 2a.
01:50
And what about for the 2b part? so by the way, this is 2a.
01:56
So in the next question, we have to find the value of k here.
02:00
This is a random variable.
02:03
So the sum of the values should be, which is equal to 1 here.
02:08
So the value of k would be, so the probability of 1 from this information, the probability of 1, which is equal to k and the probability of 2, because x can get the values from 1, 2, and 4 just only...