Number 2 (Root Locus - Compensator)
The diagram below shows a system with one pole at s = -3.
a. What is the total phase at s0 = -4.2 + j1?
b. Now you are asked to apply a compensator with one additional zero and one additional pole, D(s) = K(s + z)/(s + p). Put p and z somewhere on the real axis, so that the phase at s0 will be 180°.