Object1 of mass 8 kg moving down at -70° and 10 m/s collides and sticks to object2 of mass 12 kg which was initially moving up at 74° and 12 m/s. What is the final velocity of the combined objects?
Added by Lu-S B.
Step 1
For object1: Horizontal component = 10 m/s * cos(-70°) = 10 m/s * cos(70°) ≈ 3.42 m/s Vertical component = 10 m/s * sin(-70°) = 10 m/s * sin(70°) ≈ -9.40 m/s For object2: Horizontal component = 12 m/s * cos(74°) ≈ 3.12 m/s Vertical component = 12 m/s * sin(74°) Show more…
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