Question

Fill in the blank.\\ $\mathcal{L}\left\{\int_0^t e^{at}f(\tau)d\tau\right\} = F(s-a)(\qquad)$, whereas $\mathcal{L}\left\{e^{at}\int_0^t f(\tau)d\tau\right\} = F(s - a)(\qquad)$.

          Fill in the blank.\\
$\mathcal{L}\left\{\int_0^t e^{at}f(\tau)d\tau\right\} = F(s-a)(\qquad)$, whereas $\mathcal{L}\left\{e^{at}\int_0^t f(\tau)d\tau\right\} = F(s - a)(\qquad)$.

$Fill in the blank. ℒ{∫0^t e^atf(τ)dτ} = F(s-a)( ), whereas ℒ{e^at∫0^t f(τ)dτ} = F(s - a)( ).$

Added by Juan N.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Vishal Sharma

08/25/2021

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ODAPTT7.R.024. Fill in the blank. {[(tr)}=F(s-a -={p}sm

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Fill in the blank.\\ $\mathcal{L}\left\{\int_0^t e^{at}f(\tau)d\tau\right\} = F(s-a)(\qquad)$, whereas $\mathcal{L}\left\{e^{at}\int_0^t f(\tau)d\tau\right\} = F(s - a)(\qquad)$.

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