Question

omework: Alternating Series, Absolute vs. Conditional Convergence 1. Test the series for convergence or divergence. $\sum_{n=1}^{\infty} (-1)^n \frac{1}{\sqrt{n^3 + 1}}$ (a) $\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{\ln(n+4)}$ (b) $\sum_{n=1}^{\infty} (-1)^n \frac{3n - 1}{2n + 1}$ (c) 2. Determine whether the series is absolutely convergent, conditionally convergent, or divergent. $\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{\sqrt[3]{n}}$ (a) $\sum_{n=1}^{\infty} \frac{(-1)^n}{n^4}$ (b) $\sum_{n=1}^{\infty} \frac{\sin(4n)}{4^n}$ (c) $\sum_{n=1}^{\infty} (-1)^n \frac{2}{3n + 1}$ (d)

          omework: Alternating Series, Absolute vs. Conditional Convergence
1. Test the series for convergence or divergence.
$\sum_{n=1}^{\infty} (-1)^n \frac{1}{\sqrt{n^3 + 1}}$
(a)
$\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{\ln(n+4)}$
(b)
$\sum_{n=1}^{\infty} (-1)^n \frac{3n - 1}{2n + 1}$
(c)
2. Determine whether the series is absolutely convergent, conditionally convergent, or divergent.
$\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{\sqrt[3]{n}}$
(a)
$\sum_{n=1}^{\infty} \frac{(-1)^n}{n^4}$
(b)
$\sum_{n=1}^{\infty} \frac{\sin(4n)}{4^n}$
(c)
$\sum_{n=1}^{\infty} (-1)^n \frac{2}{3n + 1}$
(d)

omework: Alternating Series, Absolute vs. Conditional Convergence
1. Test the series for convergence or divergence.
∑n=1^∞ (-1)^n (1)/(√(n^3 + 1))
(a)
∑n=1^∞((-1)^n-1)/(ln(n+4))
(b)
∑n=1^∞ (-1)^n (3n - 1)/(2n + 1)
(c)
2. Determine whether the series is absolutely convergent, conditionally convergent, or divergent.
∑n=1^∞((-1)^n+1)/(√(n))
(a)
∑n=1^∞((-1)^n)/(n^4)
(b)
∑n=1^∞(sin(4n))/(4^n)
(c)
∑n=1^∞ (-1)^n (2)/(3n + 1)
(d)

Added by Rebecca P.

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