In human female embryos, one copy of the X chromosome is randomly inactivated in each cell between the 4-cell and 32-cell stages. A woman is homozygous recessive for an X-linked recessive trait that results in her having all unpigmented skin (Pigment is dominant and unpigmented is recessive). If she has children with a man who has all normally pigmented skin, their offspring could include: a son with all normally pigmented skin. a son with all unpigmented skin. All of the above are correct answers a son with patches of pigmented and unpigmented skin.
Added by Joshua B.
Close
Step 1
The woman is homozygous recessive for an X-linked dominant trait, so her genotype is X^C X^C. The man is unaffected, so his genotype is X^C Y. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 96 other Biology educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A woman possessing two X chromosomes has a condition where meiosis I proceeds normally, but all of her germ cells undergo non-disjunction of one of the X chromosomes in Meiosis II. Her other X chromosome behaves as would normally be expected during Meiosis II. Viable offspring resulting from a mating between this woman and a man who produces gametes containing only a single X or Y chromosome could possess which of the following sex chromosome compositions? Select all that apply. Klinefelter syndrome (XXY) Triple X Syndrome (XXX) Turner Syndrome (XO) XYY Syndrome Normal (XY) Normal (XX)
Ripujeet P.
Traits that are found on the X chromosome are said to be sex-linked. These sex-linked traits are usually designated by a superscript to the letter X. For example, XN could designate a normal allele and Xn could designate a mutant recessive allele, both occurring on the X chromosome. A colorblind female, whose mother had normal vision, and a male whose mother was colorblind produce a family. Determine the genotypes of the female and male, and the possible genotypes of their offspring using a Punnett square. Use the following notation: XN = normal allele; Xn = recessive allele 1) What is the possibility that their son will be colorblind? 2) What is the genotype of the male? 3) What is the genotype of the female? 4) What is the possibility that their daughter will be colorblind? Options for each answer: 100% 50% 25% XNXn XnY XnXn XNY XNXN
Bryan V.
A man with a specific unusual genetic trait marries an unaffected woman and they have four children. Pedigrees of this family are shown in parts $a$ through $e,$ but the presence or absence of the trait in the children is not indicated. For each type of inheritance, indicate how many children of each sex are expected to express the trait by filling in the appropriate circles and squares. Assume that the trait is rare and fully penetrant. a. Autosomal recessive trait b. Autosomal dominant trait c. X-linked recessive trait d. X-linked dominant trait e. Y-linked trait
Recommended Textbooks
Biology for AP Courses
Objective Biology for NEET
Introduction to General, Organic and Biochemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD