Question

One in 1,700 U.S. Caucasian newborns have cystic fibrosis. C is the normal allele, dominant over the recessive c. Individuals must be homozygous for the recessive allele to have the cystic fibrosis disease. Assuming Hardy-Weinberg equilibrium, how many newborns would have cystic fibrosis in a population of 10,000 people (round to the nearest whole number)?

          One in 1,700 U.S. Caucasian newborns have cystic fibrosis. C is the normal allele, dominant over the recessive c. Individuals must be homozygous for the recessive allele to have the cystic fibrosis disease. Assuming Hardy-Weinberg equilibrium, how many newborns would have cystic fibrosis in a population of 10,000 people (round to the nearest whole number)?
        
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Biology for AP Courses
Biology for AP Courses
Julianne Zedalis, John Eggebrecht
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One in 1,700 U.S. Caucasian newborns have cystic fibrosis. C is the normal allele, dominant over the recessive c. Individuals must be homozygous for the recessive allele to have the cystic fibrosis disease. Assuming Hardy-Weinberg equilibrium, how many newborns would have cystic fibrosis in a population of 10,000 people (round to the nearest whole number)?
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Transcript

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00:01 In hardy -weinbach equilibrium, the frequency of recessive allele that is represented by small q is used to determine the allele frequency of dominant allele that is represented by small p.
00:42 Now, the data which is given is 1 by 1700, 1 by 1700 caucasian newborn has cystic fibrosis, has cystic fibrosis which is only present in the individual with the homozygous, with the homozygous recessive genotype.
01:16 So, we can assume that the cystic fibrosis that is cystic fibrosis that is allele q square represent the recessive, this recessive genotype represent this recessive genotype...
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