00:01
Hello.
00:02
In this question, we're asked to calculate the work of expansion of one mole of a nitrogen gas when it's heated from 0 degrees celsius to 8 .58 degrees celsius at 1 atmosphere.
00:16
So let's get started with part a of this question.
00:21
We know that p into delta v is equal to n which is a number of moles into r, which is a universal gas constant, into delta t.
00:31
So from here we can calculate delta v which is nrt delta t by p.
00:41
We know that n is equal to 1 mole.
00:46
Delta t is equal to 858 kelvin and the pressure is equal to 180m.
00:55
So when we substitute all this, we get that delta v is equal to 1 .082 1.
01:07
Atom divided by k mole into 858 kelvin divided by an atmosphere.
01:22
Here we get the change in volume is equal to 70 .44 liters.
01:31
Now we need to find what the work done is and we know that work is equal to p into delta v.
01:39
Since we're talking about the work done due to expansion, the work done is given by minus p into delta v.
01:47
So this is equal to minus of one atmosphere and delta v...