00:02
In this question, we're given that only two forces act on a 7 .4 kilogram body, so that's why i've written the mass there is given as 7 .4 kilograms.
00:11
And the first force is acting due east at 9 .7 neutrons.
00:16
And the second force has a magnitude of 12 .4 neutrons acting 30 degrees north of east.
00:23
So we're going to use this information to get the exhilaration of this object.
00:29
So the exhilaration of the object a is going to be obtained using the formula.
00:37
F equals m .a.
00:40
So already we have the mass.
00:44
So we now want to get the force that is going to result from the combination of these two forces.
00:50
So that's the resultant force.
00:52
So the result and force, i can call it r.
00:54
It has the components, rx and ry.
01:00
Well, rx is the x component and rr is there, y component.
01:04
So we want to get the resultant component along x.
01:07
So that's going to be obtained from f1x plus f2x.
01:14
So how do we get fx and fy? so the x component is obtained by f cost theta, and the y component, fy is obtained by f sine theta.
01:27
So we want to substitute the values accordingly.
01:32
So the angle theta is the angle made from there horizontal to the angle.
01:38
So in this case, the first angle is 60 degrees.
01:42
That's the angle for f2.
01:44
So the theta here is 60 degrees.
01:46
And here the theta is zero degrees.
01:50
Okay.
01:51
Let's try and find our working here.
01:52
Here we go.
01:54
So the first angle is zero degrees.
01:57
But as you can see, the component along the x is just 9 .7.
02:04
Alternatively, the cost of 0 degrees is 1.
02:08
So that's why the x component for the fast force is 9 .7 neutrons.
02:14
And for the other force, it's going to be 12 .4 cost 60 degrees...