0:00
Let's solve the question.
00:02
The distance between two plates of a capacitor is given to us 5 .86 mm.
00:09
Suppose we denote it by d and volt equals to 600.
00:17
We have to calculate the electric field between the plates of the capacitor.
00:21
In the first part, we can write electric field is v divided by d that is 600 divided by 0 .00586 because the distance is in mm and we have to convert it into meter.
00:38
Electric field equals to 102389 .078 n per coulomb.
00:47
This is the solution for the first part.
00:50
In the second part, we have to calculate force.
00:54
Force equals to q into e if electric field is present.
01:00
Put all the values.
01:01
Charge on the electron is 1 .6 into 10 raised to power minus 19 and the value of electric field is 102389 .078...